bool cycle(int winner, int loser)
bool is_cycle(int winner, int loser)
The CS50 Tideman problem serves as an excellent introduction to graph theory and algorithmic complexity within the context of a C programming course. It forces the student to manipulate 2D arrays, implement sorting algorithms, and utilize recursion for cycle detection. The solution demonstrates how computer science can be applied to solve complex logical problems in social choice theory, providing a deterministic outcome from a set of ranked preferences. The "locking" mechanism, specifically the prevention of cycles, highlights the importance of maintaining data integrity and structural properties (the Directed Acyclic Graph) in algorithmic design. Cs50 Tideman Solution
: Do not tentatively lock a pair ( locked[w][l] = true ) before running your cycle check unless you reliably unlock it immediately if a cycle is found. It is cleaner to check the existing graph before altering the matrix. bool cycle(int winner, int loser) bool is_cycle(int winner,
// If 'from' already beats 'to' indirectly for (int i = 0; i < candidate_count; i++) // If 'from' already beats 'to' indirectly for
To achieve this, iterate through each candidate. For each candidate i , assume they are a winner. Then, iterate through all other candidates j and check if locked[j][i] is true . If any incoming edge is found, candidate i cannot be the winner. The first candidate found with no incoming edges is the winner.
if (max_index != i)